# Fading into Fog Solution Codeforces

This is an interactive problem.

There are n distinct hidden points with real coordinates on a two-dimensional Euclidean plane. In one query, you can ask some line ax+by+c=0��+��+�=0 and get the projections of all n points to this line in some order. The given projections are not exact, please read the interaction section for more clarity.

Using the minimum number of queries, guess all n points and output them in some order. Here minimality means the minimum number of queries required to solve any possible test case with n points.

The hidden points are fixed in advance and do not change throughout the interaction. In other words, the interactor is not adaptive.

A projection of point A to line ax+by+c=0��+��+�=0 is the point on the line closest to A.

The first line contains a single integer t (1t501≤�≤50) — the number of test cases.

The description of the test cases follows.

The first line of each test case contains a single integer n (2n252≤�≤25) — the number of hidden points.

For each test case, it is guaranteed that for any pair of hidden points, their x coordinates differ by at least 11. Analogously, y coordinates of any pair also differ by at least 11.

Coordinates x and y of all hidden points do not exceed 100100 by absolute value.

Interaction

To query a line ax+by+c=0��+��+�=0 you should print “? a b c” where all ab and c are real numbers up to 100100 by absolute value. For less precision issues numbers a and b must satisfy the condition |a|+|b|0.1|�|+|�|≥0.1, where |a||�| is the absolute value of a.

As an answer to the query you will get n points in the form “x_1 y_1 … x_n y_n“, where points (xi,yi)(��,��) are projections to the line ax+by+c=0��+��+�=0. It is guaranteed that each printed point is no more than 10410−4 away from the real projection point. Every coordinate is printed with at most 9 decimal places.

See the interaction example for more clarity.

To output an answer you should print “! x_1 y_1 … x_n y_n“, where (xi,yi)(��,��) are coordinates of the hidden points. You could output the hidden points in any order. The answer would be considered correct if each of the printed points is no more than 10310−3 away from the corresponding hidden point. Printing the answer doesn’t count as a query.

After printing a query or the answer, do not forget to output end of line and flush the output. Otherwise, you will get Idleness limit exceeded. To do this, use:

• fflush(stdout) or cout.flush() in C++;
• System.out.flush() in Java;
• flush(output) in Pascal;
• stdout.flush() in Python;
• see the documentation for other languages

Hacks

To make a hack, use the following test format.

In the first line output a single integer t (1t501≤�≤50) — the number of test cases.

The description of the test cases follows.

In the first line of each test case output a single integer n (2n252≤�≤25). In the next n lines output two rational numbers each. The numbers in line i should correspond to xi�� and yi�� respectively. Printed points must comply with all constraints from the input section.

Example

1
2

1 1 2.5 1

1.500000001 1.500000000 2 2


? 0 1 -1

? 0.2 -0.2 0

! 1 3 2.5 0.500000001